4S6TMP.com — IPC-2221 Standard | Bidirectional | Trace Resistance & Voltage Drop
External trace, 1 oz copper, 10°C rise (IPC-2221)
External trace, 1 oz copper, 10°C temperature rise
| Current (A) | Width (mils) | Width (mm) |
|---|---|---|
| 0.1 | 0.7 | 0.018 |
| 0.5 | 6.0 | 0.152 |
| 1.0 | 18.0 | 0.457 |
| 2.0 | 53.0 | 1.346 |
| 3.0 | 100.0 | 2.540 |
| 5.0 | 230.0 | 5.842 |
| 10.0 | 750.0 | 19.050 |
4S6TMP.com — Always verify with your PCB manufacturer's capabilities
The IPC-2221 standard provides the industry-accepted method for calculating minimum trace width based on current carrying capacity and allowable temperature rise. The formula is:
I = k × ΔT0.44 × A0.725
Where I is current in Amperes, ΔT is temperature rise in °C, A is cross-sectional area in mils², and k is a constant (0.024 for internal traces, 0.048 for external traces). The cross-sectional area is trace width × copper thickness.
To solve for width: Width = (I / (k × ΔT^0.44))^(1/0.725) / thickness
Why are external traces rated higher? External traces can dissipate heat into the air on one side, while internal traces are surrounded by insulating PCB material. This gives external traces approximately 2× the current capacity for the same width.
What temperature rise is safe? Most designs use 10°C rise for conservative, reliable operation. For cost-sensitive designs, 20°C is acceptable. Above 30°C may affect nearby components and accelerate aging.
Does this account for parallel traces or planes? No — this is for a single trace in isolation. If a trace runs over a ground plane, heat dissipation improves. If multiple high-current traces run parallel, they heat each other.
How do I calculate voltage drop? First calculate trace resistance using R = ρ × L / A, where ρ for copper is about 0.0172 Ω·mm²/m at 25°C. Then voltage drop is V = I × R.